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Accepted
a.mosallaei
Asked: 2019-08-01 12:32:22 +0800 CST

How to compare the version of something with a number in bash executable?

  • 772

I know I am asking questions a bit close together, but I can't seem to figure this out.

I have the following code:

currentver="$(lsb_release -rs)"
requiredver="18.04"
if ["$(printf '%s\n' "$requiredver" "$currentver" | sort -V | head - n1)" = "$requiredver"]
then 
    read -p "Ubuntu?: " vari
else
    read -p 'Hello?: ' var
fi

However, I always get this error: ./test.sh: line 3: [18.04: command not found. I've tried comparing currentver with 18.04 as comparing numbers, I've tried comparing them as strings, but nothing seems to work!

Any help is (as always) greatly appreciated.

scripts command-line bash

1 Answers

  1. Best Answer

    Just need spaces at either end of the if statement:

    currentver="$(lsb_release -rs)"
requiredver="18.04"
if [ "$(printf '%s\n' "$requiredver" "$currentver" | sort -V | head - n1)" = "$requiredver" ]
then 
    read -p "Ubuntu?: " vari
else
    read -p 'Hello?: ' var
fi

    whoops

    • 2