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jw_
Asked: 2019-09-12 18:44:59 +0800 CST

Let zip read source file list from a file

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For example,

zip -r output.zip file1 file2 file3

I need to put the file list "file1 file2 file3" into a text file "input_list.txt", then use the command like:

zip -r output.zip -input input_list.txt

After zip -help, the only relative information it gave is this:

-@ read names from stdin

So I tried:

'cat input_list.txt'>'zip -r -@ output.zip'

But it doesn't work.

zip

1 Answers

  1. Best Answer

    Yes you can compress multiples files listed in a list text file
    As you understood, the -@ option reads the source files names from stdin
    So, simply redirect the list to the zip program stdin

    zip output.zip -@ < files.list

    note that -r is required if the files.list contains directories

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