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Stormlord
Asked: 2020-11-16 02:50:18 +0800 CST

How to display a program output through a "dialog" window

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How can I reroute a program's output to a dialog window instead of stdout or stderr using bash?

I don't want to capture that output to a variable by using variable=$(appname) and display it afterwards by using dialog --msgbox. I want to have something like a runtime rerouting so that the program's output is displayed in that dialog window as it is generated. Not after it's finished.

Is that possible?

Thank you!

bash dialog

1 Answers

  1. Best Answer

    The --progressbox option is what you are seeking. See this example:

    { while true ; do date ; sleep 2 ; done ; } | dialog --progressbox 30 100

    It will display the data as it is printed to stdout. In your case, you can pipe your application's output to the dialog command like this:

    appname 2>&1 | dialog --progressbox 30 100

    If you want to display an OK button, when the output from appname finishes, you can use the --programbox option instead.

    See man page for details.

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