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Accepted
Praveen
Asked: 2020-11-19 11:05:37 +0800 CST

Bash printf sequence with interactive input [duplicate]

  • 772

In bash how to get printf take input interactively to print a sequence. I have tried the following:

read x; read y; printf '%s\n' {"$x".."$y"..5}
0
40
{0..40..5}

whence I am trying to get the output like this:

printf '%s\n' {0..40..5}
0
5
10
15
20
25
30
35
40
command-line bash

1 Answers

  1. Best Answer

    The problem is that you can't use variables that way in a bash brace expansion.

    Instead, you can use seq:

    read x; read y; printf '%d\n' $(seq "$x" 5 "$y")

    or more straightforwardly

    read x; read y; seq "$x" 5 "$y"

    or a C-style for loop:

    read x; read y; for ((i=x;i<=y;i+=5)); do printf '%d\n' "$i"; done

    See for example

    • 4