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Cas
Asked: 2021-01-29 07:23:38 +0800 CST

Make if statement true when variable matches one of the strings in a list

  • 772

I have a command that will output the following (curl -sSL $location | grep -o "title\=\".*\"\ agent" | grep -o "\".*\"" | grep -o "[a-zA-Z0-9].*[a-zA-Z0-9]"):

Films
TV Series

I need to make an if-statement where a variable needs to match one of those. e.g.

if [[ $option = Films ]] || [[ $option = "TV Series" ]]
then
    echo "True"
fi

But the thing is, Films and TV Series can change. The name can be different. And there is a possibility that there are more strings e.g. Films, TV Series, Music, Radio etc. etc. or movie, serie, radio, music. I need to get it so that the variable ($option) is able to match whatever output comes out of the command. It doesn't have to match every one of them, just one is enough e.g.

Output command:
Films
TV Series
Radio

$option=TV Series -> True
$option=Radio -> True

Output command:
Films

$option=Films -> True
$option=radio -> False
command-line

3 Answers

  1. Save all genres in an array without space. You can then match your token against the array (or you can also say string with words).

    #!/bin/bash

a=(Films TVSeries Music Radio)

option="TV Series"

[[ " ${a[*]} " \
    =~ " ${option// /} " ]] \
&& echo true || echo false
    • 3

  2. If the output of the command is a list as you show in the question, you can save it in an array, and check the variable against it:

    mapfile -t a < <(curl...)

option="TV Series"

[[ "${a[@]}" =~ "$option" ]] && \
  echo "$option → True" || \
  echo "$option → False"
    • 0
  3. Best Answer

    The following worked:

    if [[ "$option" == $(curl -sSL $location | grep -o "title\=\".*\"\ agent" | grep -o "\".*\"" | grep -o "$option") ]]
then
   echo true
else
   echo false
fi

    This should also work, though I haven't tested it.

    if ! [[ -z $(curl -sSL $location | grep -o "title\=\".*\"\ agent" | grep -o "\".*\"" | grep -o "$option") ]]
then 
   echo true
else
   echo false
fi
    • 0