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k314159
Asked: 2021-03-11 04:26:14 +0800 CST

lz4 command outputs to stdout unexpectedly

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Using this lz4 command:

$ apt search ^lz4$
Sorting... Done
Full Text Search... Done
lz4/focal,now 1.9.2-2 amd64 [installed,automatic]
  Fast LZ compression algorithm library - tool

$ lz4 --version
*** LZ4 command line interface 64-bits v1.9.2, by Yann Collet ***

This command normally creates a filename.lz4 file (just like gzip does):

$ lz4 -9 -k filename

However, this command does not, and instead writes to stdout when I'm not telling it to:

$ t=$(lz4 -9 -k filename)
Warning : using stdout as default output. Do not rely on this behavior: use explicit `-c` instead ! 
bash: warning: command substitution: ignored null byte in input

Why is it doing this? Is it a bug, or is there a reason documented somewhere?

bash

1 Answers

  1. Best Answer

    The behaviour appears to be a feature - not a bug. I can't find it documented anywhere except in the source code:

    /* No output filename ==> try to select one automatically (when possible) */
while ((!output_filename) && (multiple_inputs==0)) {
    if (!IS_CONSOLE(stdout)) {
        /* Default to stdout whenever stdout is not the console.
         * Note : this policy may change in the future, therefore don't rely on it !
         * To ensure `stdout` is explicitly selected, use `-c` command flag.
         * Conversely, to ensure output will not become `stdout`, use `-m` command flag */
        DISPLAYLEVEL(1, "Warning : using stdout as default output. Do not rely on this behavior: use explicit `-c` instead ! \n");
        output_filename=stdoutmark;
        break;
        .
        .
}

    On Linux, IS_CONSOLE uses isatty to determine whether file desscriptors are connected to a terminal.

    As suggested in the comment, you can use the -m option to force generation of an output file in cases where there is no tty:

    t=$(lz4 -9 -k -m filename)
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