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David Thomas
Asked: 2012-09-05 06:06:20 +0800 CST

How can I use GPRename's regex feature to reinsert the matched-group into the 'replace'?

  • 772

I've been using GPRename to batch-rename files; this is rather more efficient than individually correcting each file, but still seems to be less efficient than it might be, primarily because either I don't understand the regex syntax used, or because the regex implementation is incomplete1

Given a list of files of the following syntax:

(01) - title of file1.avi
(02) - title of file2.avi
(03) - title of file3.avi

I attempted to use the 'replace' (with the regex option selected, the case-sensitive option deselected):

(\(\d{2}\))

The preview then shows (given that I've specified no 'replace with' option as yet):

title of file1.avi
title of file2.avi
title of file3.avi

Which is great, clearly the regex is identifying the correct group (the (01)). Now, what I was hoping to do (using the JavaScript syntax) in the 'replace with' option is use:

$1

(I also tried using '$1', \1 and '\1')

This was just to check that I could access the matched group, and it seems I can't, the matched group is, as I suppose might be expected, replaced with the literal replacement string.

So, my question: is it possible to match a particular group of characters, in this case the numbers within the brackets, and then insert those into the replacement string? Therefore:

(01) title of file1.avi
(02) title of file2.avi
(03) title of file3.avi

Becomes:

01 title of file1.avi
02 title of file2.avi
03 title of file3.avi
  1. I absolutely suspect the former, personally.
regex

2 Answers

  1. Best Answer

    Unfortunately, it appears you cannot; and that it's an incomplete regex implementation at fault.

    This line at the end of all the GPRename locale translations seems to make that obvious:

    msgid "Backreferences with Regular expression cannot be use
       as $1 is considered a Perl variable."

    Since you are familiar with Perl regular expressions, may I recommend you use the excellent rename command-line utility instead?

    • Always use the -n switch first to get a preview.
    • There's a typo in your regex - it should be \((\d{2})\), with the grouping inside the escaped parentheses.

    • Example:

      $ rename -n 's/\((\d{2})\)/$1/' *.avi
(01) title of file1.avi renamed as 01 title of file1.avi
(02) title of file2.avi renamed as 02 title of file2.avi
(03) title of file3.avi renamed as 03 title of file3.avi
    • Call rename with the -v (verbose) switch and drop the -n to actually perform the renaming.
    • 7

  2. In GPRename, you can use Regular Expression like this:

        Name of file 012.txt
    Regular Expression: Name of file (\d).txt
    Replace: NewFileName_1.txt

    Where:

        1 = like $1

    You can try it. I've used \1 or \$1, but it get me \ or \$ as simple text. It is strange, but it is so.

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