root@ubuntu:/etc/openvpn# ls -l test.conf -rw-r--r-- l root root 791 Mar 20 09:23 test.conf
What does the above command mean?
root@ubuntu:/etc/openvpn# ls -l test.conf -rw-r--r-- l root root 791 Mar 20 09:23 test.conf
What does the above command mean?
That is not a command. It contains a command.
It's a prompt, followed by a command, followed by the output of the command. The command itself is:
That command displays information about the file called
test.conf
located in the current directory. Thels
command displays (or lists) information about files. The-l
flag makes it display the information in long form, rather than just showing the filename.(
ls
without a flag like-l
is most often used to list multiple files or determine if a file exists, but may be used with a file known to exist; by default in Ubuntu, issuingls filename
will highlightfilename
in a way that shows what kind of file it is, for example, it will use a certain color if it is a directory, another if it is marked executable.)The output is:
That means the file:
-rw-r--r--
doesn't start withd
)s
in-rw-r--r--
) and non-sticky (not
)rw-
for owner) but only readable by other users (r--
for group members,r--
again for others) — see the community documentation on permissionsroot
(withroot
as its group identity also)test.conf
The beginning of the line is a prompt; this is what is displayed to the user in a shell to notify the user they may enter a command. Prompts are often configured to provide helpful information to the user. Here the prompt is:
This means the current user is
root
, the machine's hostname isubuntu
(which usually means this is a live CD/DVD/USB system, but someone could name their machineubuntu
in an installed system too), and the current directory is/etc/openvpn
(which is where configuration data for OpenVPN are stored, see also the Ubuntu OpenVPN documentation).The
#
character indicates that this is a superuser shell (which is to be expected as it is owned by root, the superuser); otherwise it would have been$
(but please note that this convention is not universally followed, and some shells default to%
which does not indicate anything about the shell's capabilities).I think that you have a misunderstanding with the structure of that line.
The first sentence is telling the user at a determined computer that is in the mentioned folder:
Here you have:
and the corresponding separators between them are
@
,:
and#
The command, that is after the last separator (
#
), is:The output that you get is: