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Edward Torvalds
Asked: 2015-11-06 06:02:04 +0800 CST

how to 'not' execute alias [duplicate]

  • 772

I have set few aliases in .bashrc file. I need those aliases most of the time, but sometimes I need to run those command without options set in that particular alias.

How to not execute alias command?

bash

3 Answers

  1. Run the command with a leading \, an answer in examples: ;)

    % ls
bar  foo

% alias ls="ls -laog"

% ls
total 4292
drwxrwxr-x  4 4329472 Nov  5 15:06 .
drwx------ 95   28672 Nov  5 15:15 ..
-rw-rw-r--  1       0 Nov  5 15:06 bar
drwxrwxr-x  2    4096 Nov  5 15:06 foo
drwxrwxr-x  2    4096 Okt  2 14:29 .foo
-rw-rw-r--  1     191 Feb 25  2015 .htaccess

% \ls
bar  foo

    Slightly longer but also possible:

    command ls
    • 16

  2. You can use shell builtin command to escape aliases (and functions):

    command alias_name

    For example:

    command ls

    will run /bin/ls binary , not any alias defined as ls.

    An alternative is to use quotes:

    "alias_name"

    or

    'alias_name'

    For example:

    "ls"

    or

    'ls'

    these again will run the /bin/ls binary, ignoring any alias ls.

    • 8

  3. Alternatively, you could specify full path to command. For instance, my ls command is aliased to ls='ls --color -F'

    What one can do is either call /bin/ls or $(which ls) (for those of us who are lazy to type full path).

    Example : calling original command with flags $(which ls) -l

    • 3