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dotancohen
Asked: 2016-01-25 00:49:39 +0800 CST

How to mask stock command in Bash

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I have a function that I run often from the CLI, so I gave it the short name t:

$ which t
/home/dotancohen/.bin/t

$ cat `which t`
#!/bin/bash
ctags-exuberant -f php.tags --languages=PHP -R

$ ls -lh /home/dotancohen/.bin/t
-rwxr-xr-x 1 dotancohen dotancohen 316 Jan  3 16:58 /home/dotancohen/.bin/t

$ echo $PATH
/home/dotancohen/.bin:/usr/local/sbin:/usr/local/bin:/usr/sbin:/usr/bin:/sbin:/bin:/usr/games:/usr/local/games:/home/dotancohen/.rvm/bin

However, when I try to run the program, I get a message that I should install another app that also uses the name t:

$ t
The program 'task' is currently not installed. To run 'task' please ask your administrator to install the package 'taskwarrior'

How can I have Bash run /home/dotancohen/.bin/t when I enter t?

command-line

1 Answers

  1. Best Answer

    This is due to the fact that you have t defined as an alias (or a function), you can find it using the type builtin:

    type -a t

    Aliases, functions (and other shell builtins) take precedence over external executables.

    To run the executable t from your PATH, do:

    't'

    Or

    "t"

    Or

    \t

    Note that, just t is not a good name for a file.

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