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mcExchange
Asked: 2016-06-03 23:50:06 +0800 CST

Display images in a loop using bash

  • 772

I'm trying to display images one after the other automatically using bash. However if I use a command like this. It doesn't close the last image before opening the next. 

while read p; 
    do eog $p; 
    sleep 2; 
done < filelist.txt

Has anyone an idea how to do this?

bash

1 Answers

  1. Best Answer

    Just get the PID of the eog process and kill it before the next:

    while read p; 
    do eog $p &;
    EOG_PID=$!
    sleep 2;
    kill "$EOG_PID"
done < filelist.txt
    • 2