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Accepted
Karl Morrison
Asked: 2017-08-02 06:50:55 +0800 CST

One liner to show CPU, RAM and HDD usage

  • 772

I've seen a few posts wanting the same regarding usage, however the answers ALWAYS refer to installing some third party tool.

I do not want to install anything.

Any one liners? The following would be a nice output:

CPU 11% RAM 20% HDD 85%
command-line

2 Answers

  1. Best Answer

    You can use this

    echo "CPU `LC_ALL=C top -bn1 | grep "Cpu(s)" | sed "s/.*, *\([0-9.]*\)%* id.*/\1/" | awk '{print 100 - $1}'`% RAM `free -m | awk '/Mem:/ { printf("%3.1f%%", $3/$2*100) }'` HDD `df -h / | awk '/\// {print $(NF-1)}'`"

    The output is

    CPU 7.4% RAM 33.9% HDD 94%
    • 33

  2. For CPU usage (average of (user+system)/(user+system+idle) times over 0.1 seconds):

    (grep 'cpu ' /proc/stat;sleep 0.1;grep 'cpu ' /proc/stat)|awk -v RS="" '{print "CPU "($13-$2+$15-$4)*100/($13-$2+$15-$4+$16-$5)"%"}'

    For RAM usage ((total-available)/total):

    awk '/MemTotal/{t=$2}/MemAvailable/{a=$2}END{print 100-100*a/t"%"}' /proc/meminfo

    For HDD usage (only of the volume mounted as /):

    df | awk '/ \/$/{print "HDD "$5}'
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