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nadermx
Asked: 2017-10-24 13:44:19 +0800 CST

kill a process by name if running longer than 24 hours

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I'm currently trying to kill any program that has run over 48 hours with the name "cool-program"

I understand that if I run

ps -eo pid,cmd,comm,etime | grep -i  cool-program | grep -v grep

it gives me a list of the programs, now I'm not sure how to further filter this to only programs that have been running over a day

given the comments to have it print out a list of the pid of cool program I'm using but when I try and pipe this to kill it does not kill the programs

ps -eo bsdstart,pid,comm | grep -i ffmpeg | grep -v '^[ 0-9]' | awk '{ print $3 }'
command-line

1 Answers

  1. Best Answer

    In the man page for ps it states if you use bsdstart it will show the time the command started:

       bsdstart    START     time the command started.  If the process was
                         started less than 24 hours ago, the output format
                         is " HH:MM", else it is " Mmm:SS" (where Mmm is
                         the three letters of the month).  See also
                         lstart, start, start_time, and stime.

    Then you can use a combined command to pull the date, pid, and the command running and using grep to exclude -v the lines that start with numbers or spaces then numbers like so:

    ps -eo bsdstart,pid,cmd | grep -i cool-porgram | grep -v '^[ 0-9]'

    To kill them the command would be:

    sudo kill $(ps -eo bsdstart,pid,cmd | grep -i cool-porgram | grep -v '^[ 0-9]' | awk '{print $3}')

    Hope this helps!

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