Questions[awk](ubuntu)

In my file mytxt:

field1                    field2
------                    -------
this are numbers          12345
this letters              abc def ghi 

Let's say I want to store the first field in an array:

i=0
while read line; do 
    field_one[$i]=$(echo $line | awk '{print $1}')
    echo ${field_one[i]}  
    ((i++))
done < mytxt

That would give me the this two times in the output.

Any ideas of how could I store them in an array and get the output:

this are numbers
this letters

I have tried changing delimiters, squeezing spaces, and using sed, but I'm stuck. Any hint would be appreciated.

My final goal is to store both fields in an array.

I am new to programming!!

Can anyone help to remove the : at the first position in a timestamp: :29.06.2019 23:03:17

Presently I am trying to do it using awk/cut commands as shown below:

TDS="$(grep 'Logfile started' process.log |  awk '{print $3,$4}' | cut -d: -f2)"
echo "$TDS"


29.06.2019 23

And the output is not what I wanted! I want to print it as 29.06.2019 23:03:17.

echo '((3+(2^3)) * 34^2 / 9)-75.89' | awk "BEGIN{ print $(cat) }"

The above syntax works fine with the calculated result '1337'.

echo '((3+(2^3)) * 34^2 / 9)-75.89' | awk "BEGIN{ print $* }"

But the above syntax doesn't work, though there's no error.

Plz advise.

I can not seem to get the awk command to get the second column of data.

Bash Code:

filter_data=$(awk "{if(/$filter:/) print $2}" < scanresults_temp.txt)

printf  "$filter_data \n"

The $filter variable is either the value of Download or Upload that gets passed into the shell script. So awk uses the term Download or Upload to search for the proper row.

The file contents are:

Testing download speed................................................................................
Download: 51.13 Mbit/s
Testing upload speed................................................................................................
Upload: 57.38 Mbit/s

I am trying to get just the numbers and not anything else, ex, 51.13 and 57.38.

I know that with grep I can use the fields -A and -B to pull previous and next lines from a match.

However they pull in all lines between the match based on however many lines are specified.

grep -r -i -B 5 -A 5 "match" 

I'd like to only receive the 5^th line before a match and the 5^th line after the match in addition to the matched line and not get the lines between.

Is there a way to do this with the grep?