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αғsнιη
Asked: 2014-12-11 04:51:12 +0800 CST

What is the difference between using '+' (plus) and ';' (semicolon) in -exec command?

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I'm wondering to know that what difference is the between using + and ; at the end of -exec command when I use in find command?

find .... -exec ... \;

VS 

find .... -exec ... +
find

1 Answers

  1. Best Answer

    -exec ... \; will run one item after another. So if you have three files, the exec line will run three times.

    -exec ... {} + is for commands that can take more than one file at a time (eg cat, stat, ls). The files found by find are chained together like an xargs command. This means less forking out and for small operations, can mean a substantial speedup.

    Here's a performance demo catting 10,000 empty files.

    $ mkdir testdir
$ touch testdir/{0000..9999}

$ time find testdir/ -type f -exec cat {} \;
real    0m8.622s
user    0m0.452s
sys     0m8.288s

$ time find testdir/ -type f -exec cat {} +
real    0m0.052s
user    0m0.015s
sys     0m0.037s

    Again this only works on commands that can take multiple filenames. You can work out if your command is like that by looking at its manpage. Here's the synopsis from man cat:

    SYNOPSIS
       cat [OPTION]... [FILE]...

    The ellipsis on [FILE]... means it can take more than one file.

    + can only be used on single commands and you must have exactly one {} in the line. \; can operate with multiple zero-to-many groups.

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