I have a bunch of .html files in a directory. I want to look through each file and match a pattern (MD5). All of that is easy enough. The problem is I need to know what file the match was found in.
cat *.html | grep 75447A831E943724DD2DE9959E72EE31
Only returns the HTML page content where the match is found, but it doesn't tell me the file which it was found in. How can I get grep to show me the filename where my match is found?
I use this one all the time to look for files containing a string, RECURSIVELY in a directory (that means, traversing any sub sub sub folder)
grep -Ril "yoursearchtermhere"
R
is to search recursively (following symlinks)i
is to make it case insensitivel
is just to list the name of the files.so answering your question
grep -l '75447A831E943724DD2DE9959E72EE31' *.html
will do but you can just dogrep -Ril '75447A831E943724DD2DE9959E72EE31'
to look for that string, case insensitive, in any file in any subfolderYou can try this
Alternative to
Doing above will search recursively in the folder and subfolders and print the path of the file...
The answer posted by Cyrus is absolutely proper and is The Right WayTM to do it with
grep
if we only need to find files. When filenames need to additional parsing or operations on the matched filenames, we can resort to usingwhile
loop withif
statement. Here's an example where list of filenames comes from very commonly usedfind
+while
structure for safe parsing of filenames.I would do it like this: