Naive's questions

I have installed new Seagate hard disk to my old system and installed Ubuntu 14.04. I checked disk status using gksudo gnome-disks and resulted in Disk is OK, one attribute failed in the past. I did not get any proper links for this message. Can someone tell what does it mean ?

I'm trying to do 'upgrade' and getting following error.

$sudo apt upgrade
Reading package lists... Done
Building dependency tree       
Reading state information... Done
Calculating upgrade... Done
The following package was automatically installed and is no longer required:
  notepadqq-common
Use 'apt-get autoremove' to remove it.
The following packages will be upgraded:
  fonts-opensymbol
1 upgraded, 0 newly installed, 0 to remove and 0 not upgraded.
Need to get 0 B/110 kB of archives.
After this operation, 1,024 B of additional disk space will be used.
Do you want to continue? [Y/n] Y
E: Invalid archive signature
E: Internal error, could not locate member control.tar.{gzbz2xzlzma}
E: Prior errors apply to /var/cache/apt/archives/fonts-opensymbol_2%3a102.6+LibO4.2.8-0ubuntu5.2_all.deb
debconf: apt-extracttemplates failed: No such file or directory
dpkg-deb: error: `/var/cache/apt/archives/fonts-opensymbol_2%3a102.6+LibO4.2.8-0ubuntu5.2_all.deb' is not a debian format archive
dpkg: error processing archive /var/cache/apt/archives/fonts-opensymbol_2%3a102.6+LibO4.2.8-0ubuntu5.2_all.deb (--unpack):
 subprocess dpkg-deb --control returned error exit status 2
E: Sub-process /usr/bin/dpkg returned an error code (1)

I'm using Ubuntu 12.04 and trying to expand size allocated to Linux virtual machine, but I'm not able to find vmware-vdiskmanager or any package that installs vmware-vdiskmanager. Can anyone please tell me how to install vmware-vdiskmanager or link to download it...?

I'm trying pass year variable to re.findall, but it doesn't work(no errors). Can anyone specify where I'm going wrong?

year=2013
links = re.findall(r"('+year+'-.*\/t.*.html)", line)

Following code is to extract /support/security/*.html links from a file(urlfile contain about 1000 links) to urlsort file using regex,But i'm weak in regex can anyone show me how to do that...?

#!/usr/bin/env python
import re,sys

fileHandle = open('urlfile', 'r')
f1 = open('urlsort', 'w')
for line in fileHandle.readlines():

    links = re.findall(r"(\/support\/security\/*.html.*?)", line)
    for link in links:
        sys.stdout = f1
        print ('%s' % (link[0]))
        sys.stdout = sys.__stdout__


 f1.close()
 fileHandle.close()

I am trying download a page using wget by passing variable which holds url using python,but it didn't work.

url=http://www.example.com/support/security/


os.system("wget -P download url")

can anyone specify what is wrong with this...?

I would like a brief explanation of the following command line:

grep -i 'abc' content 2>/dev/null 

I want to write a python program to download the contents of a web page, and then download the contents of the web pages that the first page links to.

For example, this is main web page http://www.adobe.com/support/security/, and the pages I want to download: http://www.adobe.com/support/security/bulletins/apsb13-23.html and http://www.adobe.com/support/security/bulletins/apsb13-22.html

There is a certain condition I want to meet: it should download only web pages under bulletins not under advisories(http://www.adobe.com/support/security/advisories/apsa13-02.html)

 #!/usr/bin/env python
 import urllib
 import re
 import sys
 page = urllib.urlopen("http://www.adobe.com/support/security/")
 page = page.read()
 fileHandle = open('content', 'w')
 links = re.findall(r"<a.*?\s*href=\"(.*?)\".*?>(.*?)</a>", page)
 for link in links:
 sys.stdout = fileHandle
 print ('%s' % (link[0]))
 sys.stdout = sys.__stdout__
 fileHandle.close() 
 os.system("grep -i '\/support\/security\/bulletins\/' content >> content1") 

I've already extracted the link of bulletins into a content1, but don't know how to download the content of those web pages, by providing content1 as input.

The content1 file is as shown below:- /support/security/bulletins/apsb13-23.html /support/security/bulletins/apsb13-23.html /support/security/bulletins/apsb13-22.html /support/security/bulletins/apsb13-22.html /support/security/bulletins/apsb13-21.html /support/security/bulletins/apsb13-21.html /support/security/bulletins/apsb13-22.html /support/security/bulletins/apsb13-22.html /support/security/bulletins/apsb13-15.html /support/security/bulletins/apsb13-15.html /support/security/bulletins/apsb13-07.html

root@user-desktop:/etc# sudo /usr/sbin/service vsftpd restart    
restart: Unknown instance:

Guys i'm using vsftpd server and logged in using my local user account. But i want to log out from the ftp server and there is no option of log out there. Can anyone help me....?

I'm trying to install 'requests module' using easy_install but I'm getting the following error:

$ sudo easy_install requests
Processing requests
error: Not a recognized archive type: requests

If I try with pip, I get the following error:

$ pip install requests
Unknown or unsupported command 'install'

While running the simple Python program below, I'm getting the following error:

./url_test.py: line 2: syntax error near unexpected token `('                  
./url_test.py: line 2: `response = urllib2.urlopen('http://python.org/')'

import urllib2      
response = urllib2.urlopen('http://python.org/')  
print "Response:", response

# Get the URL. This gets the real URL. 
print "The URL is: ", response.geturl()

# Getting the code
print "This gets the code: ", response.code

# Get the Headers. 
# This returns a dictionary-like object that describes the page fetched, 
# particularly the headers sent by the server
print "The Headers are: ", response.info()

# Get the date part of the header
print "The Date is: ", response.info()['date']

# Get the server part of the header
print "The Server is: ", response.info()['server']

# Get all data
html = response.read()
print "Get all data: ", html

# Get only the length
print "Get the length :", len(html)

# Showing that the file object is iterable
for line in response:
 print line.rstrip()

# Note that the rstrip strips the trailing newlines and carriage returns before
# printing the output.

#!/usr/bin/env python

import httplib
import sys

#get http server ip
http_server = sys.argv[0]
#create a connection
conn = httplib.HTTPConnection(http_server)

while 1:
    cmd = raw_input('input command (ex. GET index.html): ')
    cmd = cmd.split()

    if cmd[0] == 'exit': #type exit to end it
        break

    #request command to server
    conn.request(cmd[0],cmd[1])

    #get response from server
    rsp = conn.getresponse()

    #print server response and data
    print(rsp.status, rsp.reason)
    data_received = rsp.read()
    print(data_received)

conn.close()

Error

Traceback (most recent call last):
  File "./client1.py", line 19, in <module>
    conn.request(cmd[0],cmd[1])
IndexError: list index out of range

can any one tell me why that error is coming and can anyone modify the code. it is a client side code to connect with server

my input is :GET index.html

But now my error is

File "./client1.py", line 19, in <module>
    conn.request(cmd[0],cmd[1])
  File "/usr/lib/python2.6/httplib.py", line 910, in request
    self._send_request(method, url, body, headers)
  File "/usr/lib/python2.6/httplib.py", line 947, in _send_request
    self.endheaders()
  File "/usr/lib/python2.6/httplib.py", line 904, in endheaders
    self._send_output()
  File "/usr/lib/python2.6/httplib.py", line 776, in _send_output
    self.send(msg)
  File "/usr/lib/python2.6/httplib.py", line 735, in send
    self.connect()
  File "/usr/lib/python2.6/httplib.py", line 716, in connect
    self.timeout)
  File "/usr/lib/python2.6/socket.py", line 500, in create_connection
    for res in getaddrinfo(host, port, 0, SOCK_STREAM):
socket.gaierror: [Errno -2] Name or service not known