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Martin Hope
user233233
Asked: 2014-01-11 09:06:45 +0800 CST
  • 1

I have made a simple backup script

Code:

function backups_remove_file
{
    echo ""
    echo "2. Make Backups Of Files(s)"
    echo ""
    echo "Which File You Wanna To Make Backups?"
    read back
    echo "What's The File's Name Should Be After Backups? And Where?"
    read after
    read -p "Continue (y/n)?" CONT1
    if [ "$CONT1" == "y" ]; then
        tar -cvpzf "$after.tar.gz" "$back"
        echo "Backups File Successful !" ;
    else
        echo "Backups File Unsuccessful !" ;
    fi
}

But there is one small problem I could not fix. When it shows

Which File You Want To Make Backups?

if you write for example "test" after that, and for the next question

What's The File's Name Should Be After Backups? And Where?

if you write for example "test1", then there will be a safety issue if they want to continue or not if type y it will output:

taking: test: can not state: No such file or directory
tar: Exiting with failure status due to previous errors
 Backups File Successful!

The output in that case should be Backups File Unsuccessful!. What should I do to get the expected output in this case?

bash
Martin Hope
user233233
Asked: 2014-01-10 01:24:59 +0800 CST
  • 1

I want to make a script that shows what type of file is

for example :

./file.sh haha test lala ssss

haha --> file

test --> directory

lala --> symbolic link

ssss --> executable

Im trying to do like this but I dont get the same result ...

#!/bin/bash

function check_symboliclink
{
echo "Write symbolic link"
read something
find $something -type l 
echo "$something  symbolic link";
}

check_symboliclink

Is there someone have better idea to do like the example ?

command-line