I have a directory containing different text files such as:
ajac001a00.24o
ajac001a15.24o
ajac001a30.24o
.
.
areg001a00.24o
areg001a15.24o
areg001a30.24o
.
.
I need to combine these text files separately, starting with the same four characters, such as
cat *ajac* > ajac_combined
cat *areg* > areg_combined
How can I do this using a loop? There are too many files starting with different characters that exist, therefore this cannot be done using cat command manually.
I have a text file. This file includes characters and numbers as follows:
ANKR00TUR_R_20183240000_01D_30S_MO.rnx: 2018 11 20 00 00 0.0000000 GPS TIME OF FIRST OBS
brmu3350.14o: 2014 12 1 0 0 0.0000000 GPS TIME OF FIRST OBS
KNY12040.14o: 2014 7 23 0 0 0.0000000 GPS TIME OF FIRST OBS
rinex_quantity:grep "TIME OF FIRST OBS" * > time_of_first_epochs
I need to extract only 4 digits numbers and store them into another file as follows:
2018
2014
2014
I applied the following code but it extracts all 4 digit numbers:
grep -Po "\d{4}" data
2018
3240
2018
0000
3350
2014
0000
1204
2014
0000
I have several files whose extensions are .gz with similar filenames to:
ANKR00TUR_R_20183350000_01D_30S_MO.crx.gz
I need to read the first four characters of these files' names and store these characters in a file. How can I do this?
I need to duplicate rows in text file with a specific number of times. For example my data file is:
jplg3350.18i
jplg3360.18i
jplg3370.18i
I need to duplicate the lines three times as follows;
jplg3350.18i
jplg3360.18i
jplg3370.18i
jplg3350.18i
jplg3360.18i
jplg3370.18i
jplg3350.18i
jplg3360.18i
jplg3370.18i
I have 6 directories. Each directory includes 8 text files. These text files share the same prefix. I need to combine these text files as follows;
Assume, first text file in directory_1 contains files containing the text abc_1, directory_2 contains files with the text abc_2 and so on. Merged text file for the first text files needs to be in this form:
abc_1
abc_2
abc_3
..
abc_6
The second, third... and eighth text files also need to be combined with the same rule.
awk -v input="$constrained" '
BEGIN {
n = split(toupper(input), user)
fmt = "%-4s %-8s NNN 0.050 0.050 0.050\n"
}
{print}
/<< matched line >>/ {
for (i=1; i<=n; i++)
printf fmt, user[i], user[i]"_GPS"
exit
}
' ./text_data > text_data_2
In the above codes, I want to define variable for 0.050 0.050 0.050. I tried using with
echo -n "##### numeric value? ####?"
read value
fmt = "%-4s %-8s NNN $value $value $value\n"
but within the quotation marks, $value variable cannot be defined. How can I define this variable inside the quotation marks?
2 METEOROLOGICAL DATA VERSION /
8 PR TD HR ZW ZT WD WS RI # / TYPES OF MOD/TYPE/ACC
3979316.8350 1050313.7180 4857065.7030 592.1910 PR SENSOR POS XYZ/H
END OF HEADER
10 1 1 0 0 15 927.9 4.3 99.1
10 1 1 0 1 15 927.9 4.3 99.1
10 1 1 0 2 15 927.9 4.3 99.1
10 1 1 0 15 15 927.9 4.2 99.1
10 1 1 0 16 15 927.9 4.2 99.0
10 1 1 0 30 15 927.7 4.1 99.1
10 1 1 0 31 15 927.7 4.1 99.1
10 1 1 0 45 15 927.5 4.1 99.1
10 1 1 0 46 15 927.5 4.0 99.1
10 1 1 1 0 15 927.4 4.1 99.1
10 1 1 1 1 15 927.4 4.1 99.1
In this example of text data, how can I extract all 0,15,30,45 in 5th column of numeric data orderly, after the "END OF HEADER" part as follows;
10 1 1 0 0 15 927.9 4.3 99.1
10 1 1 0 15 15 927.9 4.2 99.1
10 1 1 0 30 15 927.7 4.1 99.1
10 1 1 0 45 15 927.5 4.1 99.1
10 1 1 1 0 15 927.4 4.1 99.1
I have two text files, whose content is as follows;
data_1:473428800.0 0 0.000004 1.00 WETZTROPMCIL #4 columns, several lines
473429100.0 0 0.000002 1.00 WETZTROPMCIL
data_2:473428800.0 0 2.100000 1.00 DRYTROPMCIL #4 columns, several lines
473429100.0 0 2.200000 1.00 DRYTROPMCIL
I need to add each line of the 3rd column of one file to the respective line of the 3rd column in the other file, and substitute these sums to the 3rd column of data_1, in a new file, as below;
merged_data= data_1:473428800.0 0 2.1000004 1.00 WETZTROPMCIL #4 columns, several lines
473429100.0 0 2.2000002 1.00 WETZTROPMCIL
Assume I have three text files, data_1, data_2, and data_3. Firstly, I need to copy data_1 inside to another new text file (new_data). Then I need to add data_2 to new_data (includes data_1). Finally I need to add data_3 to new_data (includes data_1 and data_2).
For example,
data_1= 10 10 10
15 15 15
data_2=5 5 5
data_3= 11 11 11
12 12 12
new_data= 10 10 10
15 15 15
5 5 5
11 11 11
12 12 12
How can I perform this task as a sequential way for multiple text files?
I have 24 directories in a specific directory (main_directory). Each 24 directory have a text file whose name is DATA.txt.
I need to use grep command to extract below specific pattern for each text file;
2* x = 3800689.6402 y = 882077.3636 z = 5028791.2953
2* x = part is constant for all DATA.txt. The other numeric numbers are variable. I need to extract above line for each DATA.txt and save them into another text file. Which script I can use for this process?
I have a directory consists of several files. Files name are as follows;
0102920.05o
0203920.05o
0304920.05o
....
I need to add "0" for all files after the first 4 numbers like;
01020920.05o
02030920.05o
03040920.05o
Is there a way to do it with bash or perl?
I installed libx11-dev with following command;
sudo apt-get install libx11-dev
I need libX11.a, libX11.so and Xlib.h files. When I searched these files I couldn't locate them. I need to install libX11.a into /usr/lib/X11, libX11.so into /usr/lib/X11 and Xlib.h into /usr/include/X11.
How can I install these files?
I have text file like (the specific part of the whole file);
! lat long elev (m)
! 44.5199005 11.6468000 50.4276
I need to extract second line and save them in another text file. The numbers are variable and "!" syntax is also exist several times in the text. For the first line there is always 8 spaces between "!" and "lat" but this is not the case for the second line. Is there any command available to allow me to extract next line after grep "! lat" text
I have a day-and-month text file like this:
day=
8
9
10
15
1
month=
3
6
7
10
1
I need to add "0" to lines, including only one-digit numbers. I need to write a loop to find a one-digit number in all the lines and add "0" to the left of the number like;
day=
03
06
07
10
01
month=
03
06
07
10
01
i is an integer (lets say 4). I have three text files (a,b,c) contain single lines with strings, total number of lines of files equal to i (4). For example "a" file contains;
trm320
abc000
dfg1002
der5205
I need to create the output (on the screen or in the text file) with loop like;
a(1) b(1) c(1) (first line of a,b,c files)
a(4) b(4) c(4) (last line of a,b,c files)
What kind of loop do I need to create?
ffmj0010.09o:FFMJ MARKER NAME
ffmj0020.09o:BRMU MARKER NAME
In this text file (2 lines and no space between the lines) I need to extract 4 characters after ":" ("FFMJ", "BRMU") and save them in another text file. Which command do I need to use?
I'm using a software, after the execution MIT servers sent me an email. To receive this e-mail I need to install "mail" program in my ubuntu. I tried the below way but it didn't work;
sudo apt-get install mailutils
then I chose internet-Site configuration, and, System mail name:[email protected] was set.
Is there a suitable way to setup "mail" program for receiving purposes?
the software's script to send an email is:
set umail = 'mail -s'
set JOBSTAT = `echo 'sh_gamit '$expt $yr[1] ${doy}`
${umail} "$JOBSTAT" ${mailto} < ${cpth}/tmp.mail.$ts >& /dev/null
How can I set LANG=en_US.UTF-8 in .bashrc? When I looked into .bashrc, I can't find any LANG settings.
I need to check out which shells are available. Which command gives me available (installed shell like, tcsh, csh, bsh) shells in terminal?
I have a tarball (x.tar) in home/sermet directory. When I'm in different directory on terminal like, /opt#, I want to untar the x.tar in its current directory (home/sermet). How can I perform it?