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Trey Parkman
Asked: 2010-06-12 13:12:54 +0800 CST

Run bash script with command line arguments

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I want to do

/usr/bin/bash myscript.sh -args

which, as it stands, runs the script but doesn't pass the args to it. I realize that the conventional syntax is simply

./myscript.sh -args

but I'm curious as to what I need to do in order to call the script from bash explicitly.

bash unix-shell

2 Answers

  1. Try running the script in debug output mode

    /usr/bin/bash --verbose myscript.sh -args
    • 1

  2. Please provide information about your operating system. Having 'bash' located at "/usr/bin/bash" tips me off that you're probably not running one of the more common GNU/Linux distributions.

    On that note, what does the she-bang of the script look like? If it's any different from the following, then you're not doing the equivalent with your bash command:

    #!/usr/bin/bash

    One other suggestion I can pull out of the blue is to try escaping the parameters to bash, just in case there's some strange getopt thing going on.

    /usr/bin/bash -- myscript.sh -args
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