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Accepted
Dhanushka Ekanayake
Asked: 2021-05-12 21:10:31 +0800 CST

How to get the nearest subdirectory of a file as output in PowerShell?

  • 772

I need to get only the nearest subdirectory and file name from the file path as follows.

Ex:-

(1)E:\Dump\DumpText-1.txt - Dump\DumpText-1.txt

(2)E:\Dump\SubDump1\DumpText-1.txt - SubDump1\DumpText-1.txt

(3)E:\Dump\SubDump3\Sub_SubDump1\DumpText-1.txt -Sub_SubDump1\DumpText-1.txt

My PowerShell Script as follows:

Get-ChildItem $directoryPath -Recurse | ForEach-Object -Process {if (!$_.PSIsContainer) {$_.FullName; $_.FullName -replace "^.*?\\"; " "}}
powershell directory devops

2 Answers

  1. Best Answer

    You could use the Directory property of the object:

    Get-ChildItem $directoryPath -Recurse -File | ForEach-Object {
    "$($_.FullName) - $($_.Directory.Name)\$($_.Name)"
}

    just use the name of the Directory object and then the name of the file.

    • 4

  2. The easiest way in my eyes is to split the string at the backslashes:

    $splitString = "E:\Dump\SubDump3\Sub_SubDump1\DumpText-1.txt" -split "\\"

    (since the backslash is the escape character, it has to be escaped by a second backslash).

    $splitString now is an array of all the parts between the backslashes. Now you can access the last and the second-last part of this array by $splitString[-1] (the filename) and $splitString[-2] (the name of the direct parent folder).

    • 2