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Kumar
Asked: 2010-02-02 03:18:46 +0800 CST

Grep a word from a file

  • 772

How can i grep a nearer word from a file ?

E.g 

04-02-2010  Workingday
05-02-2010  Workingday
06-02-2010  Workingday
07-02-2010  Holiday
08-02-2010  Workingday
09-02-2010  Workingday

I stored above data in a file 'feb2010',

By this commend i stored date in one variable date=date '+%d-%m-%Y'

if date is 06-02-2010 , i want to grep "06-02-2010" with Workingday

and want to store the string "Workingday" in a variable

  • How can i do this ?

  • Is there any other option ?

linux shell grep

4 Answers

  1. Best Answer

    Do you mean something like that?

    DATE=$(date '+%d-%m-%Y')
DAY=$(grep $DATE feb2010 | awk '{ print $2 }')
echo $DAY

    This greps for your $DATE and selects the second column for the output via awk and stores this output in the variable $DAY.

    • 4

  2. month = " 06-02-2010 Workingday " && grep search-string $month

    • 0

  3. Try 

    #!/bin/sh
variable=`grep "06-02-2010" feb2010`
OR
variable=grep "$(date +%d-+%m-%Y)" feb2010
echo $variable should return the good output
    • 0

  4. This question doesn't post an OS so here's how you would do this under windows powershell:

    ((select-string -path .\grepme.txt -pattern (get-date -uformat "%m-%d-%Y")).line).split(' ')[2]

    Select-string is grep's equivalent

    • 0