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acgbox
Asked: 2022-10-01 08:55:37 +0800 CST

how to extract values from files, compare it with a variable and send to out file

  • 772

I have myfolder with this files:

ls myfolder
filefoo filebar filefoobar

For example, the content of filefoo is:

total: 379400041
cache_object://localhost/active_requests    379400041       6778    0-13955161 0-14111309 0-12250718 0-11422369 0-11901178 0-11781835 0-12687756 0-17663930 5-110207691 6-123940805 2-39477289 0-0 0-0 0-0 0-0 0-0 0-0 0-0 0-0 0-0 0-0 0-0 0-0 0-0
bla bla bla

Note: the rest of the files have the same internal structure, but the numbers change

So the value I'm interested in extracting from these files is "total: number". this value is always in the first row of each file:

find myfolder -type f -exec awk '/^total:/{print $NF}' {} +
379400041
35402285
8589934592

And I should compare it with this variable:

max="1073741824"

So what I need is that if any of these values exceeds the $max variable (value > $max), it should output the file to an output list. Example (non-functional):


if (( "value" > "$max" )); then
# or if [ "value" -gt "$max" ]; then
    the command to send the file to a list is missing > output.lst
 else
    echo "do nothing"
fi

expected output:

cat output.lst
filefoobar

Because filefoobar has 8589934592 and this value > $max

How to do that? thanks

linux

1 Answers

  1. Best Answer

    Try this:

    $ max="1073741824"
$ ( cd myfolder
    for file in *
    do
        if (( `awk <$file '/^total/ {print($2)}'` > $max ))
        then echo $file
        fi
    done
) >output.lst

    Note the use of grave accents, and that there are no spaces around the "=".

    And of course there is no error checking here.

    • 1