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Accepted
gremo
Asked: 2023-02-14 05:58:41 +0800 CST

Bash sed command with sed itself as replacement, quotes not outputted

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I need to modify the content of a file, with the following sed command (which works fine):

sed -i '[email protected].*@'"date.timezone = $TZ"'@' $PHP_INI_DIR/conf.d/symfony.ini

This line should be injected in a script before the exec:

#!/bin/sh
set -e

exec "$@"

So i need another sed to say "replace before exec":

sed '/exec/i \sed -i '[email protected].*@'"date.timezone = $TZ"'@' $PHP_INI_DIR/conf.d/symfony.ini\n' docker-php-entrypoint

The problem are quotes which are not outputted:

#!/bin/sh
set -e

sed -i [email protected].*@"date.timezone = $TZ"@ $PHP_INI_DIR/conf.d/symfony.ini

exec

Putting a backslash \ before '[email protected] does nothing. Any suggestion?

bash

2 Answers

  1. Best Answer

    This is a shell issue. The shell does "quote removal", so you need to study how quotes behave in the shell. Single quotes can't be nested nor escaped. You have to end the single quoted string to insert a single quote.

    sed '/exec/i \sed -i '\''[email protected].*@'\''"date.timezone = $TZ"'\''@'\'' $PHP_INI_DIR/conf.d/symfony.ini\n'
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  2. You can use double quotes within single quotes and vice versa to escape the quotes:

    sed '/exec/i \sed -i '"'"'[email protected].*@"date.timezone = $TZ"@' $PHP_INI_DIR/conf.d/symfony.ini\n'"'"' docker-php-entrypoint

    This way, the single quotes are escaped within the single quotes and the double quotes are used within the escaped single quotes.

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