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Accepted
LanceBaynes
Asked: 2011-01-20 13:28:25 +0800 CST

sed with several matches

  • 772

The two "sed lines" only differ by a "\n" below..
How can i get this output [no new line before the </pre>]? [ http://pastebin.com/raw.php?i=ED34jvtF ]:
.
.
something3
</pre>
something4
.
.


$ echo -e 'something1\nsomething2\nsomething3\n\n</pre>\nsomething4\nsomething5'; echo "######################################"; echo -e 'something1\nsomething2\nsomething3\n\n</pre>\nsomething4\nsomething5' | sed -e N -e N -e "s#\n</pre>#</pre>#g" -e P -e D
something1
something2
something3

</pre>
something4
something5
######################################
something1
something2
something3</pre>
something4
something5
$
$ echo -e 'something1\nsomething2\nsomething3\n\n</pre>\nsomething4\nsomething5' | sed -e N -e N -e "s#\n</pre>#\n</pre>#g" -e P -e D
something1
something2
something3

</pre>
something4
something5
$

linux bash fedora sed

1 Answers

  1. Best Answer

    Give this a try:

    sed 's|\(.\+\)\(</pre>\)$|\1\n\2|;t;N;\|\n</pre>$|s|^[[:blank:]]*\n||;P;D' inputfile

    The result:

    something1
something2
something3
</pre>
something4
something5
######################################
something1
something2
something3
</pre>
something4
something5

    Notice that both instances of </pre> are on a line by themselves without a preceding blank line.

    Edit: Fixed a problem with deleting the wrong lines.

    • 2