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rahrahruby
Asked: 2012-05-12 13:25:52 +0800 CST

changing directory in bash script

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I have the following script:

cd "/usr/local/bin/"     
/sbin/startproc ./program1

I have a license in the /usr/local/bin directory and if the program isn't started from there it won't launch correctly.

The cd "/usr/local/bin" doesn't seem to be doing the trick.

scripting bash

2 Answers

  1. Taking a peek at startproc's man page, it looks like it wants full path.

    Have you tried the cd and specifying the full directory, like so?

    cd /usr/local/bin
startproc /usr/local/bin/program1

    On thing I'd do afterwards is add the following line immediately after the startproc line;

    echo -e "exit code is $?"

    That can tell you what error startproc is throwing, and what the problem might be, according to this exit code list for the program:

    0 Success
    1 Generic or unspecified error
    2 Invalid or excess argument(s)
    4 Insufficient privilege(s)
    5 Program is not installed
    7 Program is not running

    That should give you a better peek into what's up if the full path doesn't work.

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  2. You haven't said anything about the kind of system you're doing this on, but typically a utility with a name like startproc does its own setup — often including setting a default directory. I suggest you find your system's documentation for startproc and see how to make it do what you need, or failing that startproc the script that changes directory.

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