I have been given the following IP 192.168.14.137/25 and asked to divide the network into 2.
This is what I've come up with:
- The subnet mask is 255.255.255.128
- The network address is 192.168.14.128
There are a total of 128 available addresses (including the network address and broadcast address)
To divide the network we create two subnets:
- 192.168.14.128/26
- 192.168.14.192/26
This will have a subnet mask of 255.255.255.192
Am I missing anything, or is this correct?
Yes, everything is correct in your calculations.