Facing a problem where we are running out of available network addreses, we are currently on bog standard 192.168.1.x range.
Reading about making more ips available and subnets and think i have just about got my head around it.
My question is, is it as simple as saying to my router (currently handling dhcp) use ip range 172.16.0.1 / 255.255.254.0 and it should hand out ips from 172.16.0.1 to 172.16.1.255? all of which are able to talk to each other?
Or have i got wrong end of stick here? On basis of above is there a way of staying on 192.168.x.x and getting more hosts, we are currently using too many but expansion plans wont see more than another 100 at most in next 5 years.
if you need any more detail please let me know.
Thanks
RFC 1918 identifies a number of private address ranges, including 192.168.0.0/16. This block includes all addresses from 192.168.0.0 to 192.168.255.255, which ought to be sufficient for your network.
You're currently using 192.168.1.0/24, which is a block of 254 addresses. If you subtract a bit from the network mask -- 192.168.0.0/23 -- you'll double your available addresses. Your range will extend from 192.168.0.0 to 192.168.1.255. That corresponds to a "netmask" of 255.255.254.0.
You'll get the same thing using 172.16.0.0/23, which is what you've identified in your question. Same number of addresses, just a different range of numbers. Note that according to RFC 1918 that block is bigger; 172.16.0.0/12 includes over 1,000,000 addresses.
You could migrate from 192.168.1.0/24 to 192.168.0.0/23.
With such subnet there are 510 hosts will be available