A simple version of this question has been asked before (and links to VMware site for simple scenarios exist) - but this is a bit more complicated. I have 4 snapshot scenarios under VMware esxi 5.5:
and I want to know what happens when I click "DELETE ALL" snapshots. Is this correct?
- Scenario 1: A and B will be merged, and there will be NO more snapshots
- Scenario 2: B will be thrown away, and there will be NO more snapshots
- Scenario 3: A and B will be merged, C will be thrown away, and there will be no more snapshots
- Scenario 4: A and B and C will be merged, D and E will be thrown away, and there will be no more snapshots.
According to VMware, deleting any snapshot merges it into the parent only if it is the current chain. But I think their article is poorly worded - and it conflicts with other VMware postings that suggest snapshots below the current (you are here) state in the current chain are simply discarded
When you choose "Delete all Snapshots", all of the snapshots go away and you end up with a single disk file.
1.First Scenario is last disk are ready in Write mode at B 2.You reverting from last disk and going to First disk data.... 3.same like 2 scenario but disk stage is different 4.scenario 4 is wrong because metedata will not create the new tree...called E ....
I hope you can understand my explanations