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corsiKa
Asked: 2011-04-16 22:27:42 +0800 CST

ignore lines grep

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I have a very annoying message being output from a process I'm running. I'd rather not remove the line, but simply remove it with grep

The messages to ignore all contain the word "requests". I could easily ONLY these lines with

$> myproc | grep requests

How would I make grep instead IGNORE lines with the word requests?

regex grep ignore

2 Answers

  1. Best Answer

    Just use the -v option:

    myproc | grep -v requests

    • 8

  2. Sorry can't resist:

    myproc | perl -ne "/requests/ or print"

    that's a perl one liner that uses -e to execute code on the command line, and -n to wrap it in a while loop reading one line at a time. The /requests/ part is a match against any line that contains the word 'requests`. Putting it all together says, "if the line doesn't contain the word 'requests', print it out."

    This is a contrived example since Robin Green points out that grep -v works just fine in your case. However you can extend this perl one liner to make an arbitrarily complex filter.

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