How to output column with special patterns

This will do exactly as you want

#!/bin/bash
array=(
[0]="scatman"
[1]="batman"
[2]="superman"
)
count=0
while read line; do
    for i in "${array[@]}";
    do
    if [[ $count == 3  ]]; then
    count=0
    fi
    if [[ $line == ${array[$count]} ]]; then
    #echo "$line"
    printf "%s " $line

    # uncomment if you want every word on a new line
    #echo "$line" >> newfile.txt # each word on a line
    #or
    # uncomment if you want all will be on one line
    #printf "%s " $line >> newfile.txt

    count=$((count+1))
    else
    continue
    fi

    done

done < file.txt #this is your original file

Will print out every word on a new line like this:

scatman
batman
superman
scatman
batman
superman
scatman
batman
superman
scatman
batman
superman
scatman
batman
superman
scatman

or on a one line like this:

scatman batman superman scatman batman superman scatman batman superman scatman batman superman scatman batman superman scatman

This can be done with grep and awk:

cat words.txt |
grep -E 'scatman|batman|superman' |
awk '{
      last_word = cur_word
      cur_word = $0
      if (cur_word == last_word)
        next
      else
        print $0
      }' < word.list 

The grep -E allows an extended Regular Expression that lets you use | as an or for search targets. The awk code looks for repeated words and skips them.

You can do all this in one line, if you want to:

cat words.txt | grep -E 'scatman|batman|superman' | awk '{ last_word = cur_word; cur_word = $0; if (cur_word == last_word) next; else print $0 }' < word.list`