Valeriu's questions

i have a task, where i should create br1 without link to eth* and give to this br1 access to internet. I have CentOS7. I have created the interface br1:

DEVICE=br1
TYPE=Bridge
ONBOOT=yes
BOOTPROTO=static
IPADDR=192.168.1.1
NETMASK=255.255.255.0
NM_CONTROLLED=no

In iptables i have written this:

iptables -t nat -A POSTROUTING -s 192.168.1.0/24 -j SNAT --to-source 192.168.122.1

192.168.122.1 for example my main interface, that has access to internet.

My question: it is enough for get access to internet from my virtual machine on KVM, or i need do something else. Maybe i need some FORWARD rules. Because virbr0 interface working, but my br1 no.

i want to create bridge for my virtual machine. And i want to have access in internet from my virtual bridge. What i did:

DEVICE=br1
TYPE=Bridge
ONBOOT=yes
BOOTPROTO=static
IPADDR=192.168.1.1
NETMASK=255.255.255.0

I have bridge in my network (by dhcp), that linked with eth0:

br0: flags=4163<UP,BROADCAST,RUNNING,MULTICAST>  mtu 1500
        inet 192.168.110.14  netmask 255.255.255.0  broadcast 192.168.110.255

br0:

DEVICE=br0
TYPE=Bridge
ONBOOT=yes
BOOTPROTO=dhcp

eth0:

TYPE=Ethernet
BOOTPROTO=dhcp
DEFROUTE=yes
PEERDNS=yes
PEERROUTES=yes
NAME=eth0
DEVICE=eth0
ONBOOT=yes
BRIDGE=br0

iptables command:

iptables -t nat -A POSTROUTING -s 192.168.1.0/24 -j SNAT --to-source 192.168.110.14

but it doesn't working.

ping -I br1 8.8.8.8
PING 8.8.8.8 (8.8.8.8) from 192.168.1.1 br1: 56(84) bytes of data.
^C
--- 8.8.8.8 ping statistics ---
61 packets transmitted, 0 received, 100% packet loss, time 59999ms

What i did wrong ? Please help.

i should use chroot for my ftp directory at my site: My php-fpm.conf:

[mysite.com]
listen = /var/run/php7-fpm-chroot-filemanager.sock
chroot = /var/www/mysite.com/fileman
chdir = /
user = filemanuser
group = filemangroup
pm = dynamic
pm.max_children = 5
pm.start_servers = 2
pm.min_spare_servers = 1
pm.max_spare_servers = 3

My nginx.conf part:

    location ~* /fileman/(.+\.php)$
    {

            root /var/www/mysite.com/;
            include /etc/nginx/fastcgi_params;
            if (!-f /var/www/mysite.com$fastcgi_script_name) {
                    return 405;
            }
            fastcgi_index index.php;
            fastcgi_pass unix:/var/run/php7-fpm-chroot-filemanager.sock
            fastcgi_param SCRIPT_FILENAME /var/www/mysite.com$fastcgi_script_name;
    }

After restarting of services, i see at the page:

File not found. 

In the logs of nginx:

2017/02/24 20:12:22 [error] 18390#18390: *108 FastCGI sent in stderr: "Primary script unknown" while reading response header from upstream, client: 192.168.110.25, server: www.mysite.com, request: "GET /fileman/index.php HTTP/1.1", upstream: "fastcgi://unix:/var/run/php7-fpm-chroot-filemanager.sock:", host: "www.mysite.com"

Without chroot options, everything is ok. Where i have an error ? Please help.

I have a file, where i should make "uniq" and show result. My file:

178.57.66.225 fxsciaqulmlk
178.57.66.225 fxsciaqulmlk
178.57.66.225 fxsciaqulmlk
178.57.66.225 faaaaaa11111
178.57.66.215 terdsfsdfsdf
178.57.66.215 terdsfsdfsdf
178.57.66.215 terdsfsdfsdf
178.57.66.205 erdsfsdfsdf
178.57.66.205 erdsfsdfsdf
178.57.66.205 erdsfsdfsdf
178.57.66.205 erdsfsdfsdf
178.57.66.205 abcbbabab
178.57.66.205 abcbbabab
178.57.66.205 abcbbabab
178.56.66.225 fxsciulmla
178.56.66.225 fxsciulmla
178.56.66.225 fxsciulmla
178.57.67.225 faaaa0a1111

My script:

for i in $(uniq -c /root/log | awk '{print $1}'); do
if [ $i -gt 2 ]; then
s=$(uniq -c /root/log | awk '$1 == '$i | awk '{print $3}')
ss=$(uniq -c /root/log | awk '$1 == '$i | awk '{print $2}')
echo "The bot is user $s with ip $ss"
fi
done

All ok, but my output is not correct:

The bot is user fxsciaqulmlk
terdsfsdfsdf
abcbbabab
fxsciulmla with ip 178.57.66.225
178.57.66.215
178.57.66.205
178.56.66.225
The bot is user fxsciaqulmlk
terdsfsdfsdf
abcbbabab
fxsciulmla with ip 178.57.66.225
178.57.66.215
178.57.66.205
178.56.66.225
The bot is user erdsfsdfsdf with ip 178.57.66.205
The bot is user fxsciaqulmlk
terdsfsdfsdf
abcbbabab
fxsciulmla with ip 178.57.66.225
178.57.66.215
178.57.66.205
178.56.66.225
The bot is user fxsciaqulmlk
terdsfsdfsdf
abcbbabab
fxsciulmla with ip 178.57.66.225
178.57.66.215
178.57.66.205
178.56.66.225

I am making it during 2 days, and i can't understand where i make mistake ? Please help.

When, i increase number of uniq in condition:

if [ $i -gt 2 ]; then

I have a normal log:

The bot is user erdsfsdfsdf with ip 178.57.66.205

Where i have mistake ?

I have the text, that contains some lines. So, i need to make GREP of several lines. For example, i have repeating text and i should GREP get lines, that have this repeating key-words.

grep -o "test|test2" textfile

My text:

123|never for your|test
123421|never for your|test2
123412|never for your|test3
12341|never for your|test4
12311|never for your|test2
123312312|never for your|test
123321312|never for your|test2

I should have:

123|never for your|test
123421|never for your|test2
123312312|never for your|test
123321312|never for your|test2

It works, but it doesn't work how i want. It searchs in text, all words "test" & "test2". But i want to get textblocks, like some pattern, where only after "test" comes "test2". Have you got any ideas ?

I have a column, with some words:

scatman
batman
superman
scatman
scatman
batman
superman
scatman
scatman
batman
superman
scatman
batman
WWWWWWWW
superman
scatman
batman
superman
scatman

I should make some patterns, where i need to have word by word three words: scatman, batman, superman. Where, i have repeat words, like scatman & scatman on line 4 & 5 or where i have other words, i should cut them I have written:

grep "scatman\|batman\|superman" file

Ok, i have rejected word WWWWWWWW, but i can't understand how to show my column word by word. Ihave in result:

scatman
batman
superman
scatman
scatman
batman
superman
scatman
scatman
batman
superman
scatman
batman
superman
scatman
batman
superman
scatman

At line 4 & 5 i have repeat words, but i don't like that. Where i have the mistake ?

i have table with columns. In first column, i have time, when the user has logged, in second column, i have a name of user.

13:15:39  fxs1cia1qulm1lk  
13:15:39  fxs1cia1qulm1lk  
13:15:39  fxs1cia1qulm1lk  
13:15:42  faaaa2aa11111  
13:15:49  terd1sfsd11fsdf  
13:15:49  terd1sfsd11fsdf  
13:15:49  terd1sfsd11fsdf  
13:15:59  21erdsf123sdfsdf   
13:15:59  21erdsf123sdfsdf   
13:15:59  21erdsf123sdfsdf   
13:15:59  21erdsf123sdfsdf   
13:17:50  abcasbbabadab  
13:17:50  abcasbbabadab  
13:17:50  abcasbbabadab  
13:17:50  abcasbbabadab   
13:19:19  fxs1ce1iulmla   
13:19:19  fxs1ce1iulmla  
13:19:19  fxs1ce1iulmla   
13:20:42  faaa2a0a1111

So, what i should do. I should to make uniq uperation with this two columns, Andm if the time of user logging and the name of user are same, i should say, that user has logged more than 3 times. I have written short script:

log_file=/root/log
temp_file=/root/temp
temp_file2=/root/temp2

cat /dev/null > $temp_file
cat /dev/null > $temp_file2
cat /dev/null > $result_file

cat $log_file | awk '{print $1}' | tail -n 20 > $temp_file
cat $log_file | awk '{print $5}' | tail -n 20 > $temp_file2

for i in `uniq -c $temp_file | awk '{print $1}'`; do
for y in `uniq -c $temp_file2 | awk '{print $2}'`; do
if [ $i -gt 3 ] && [ $y -gt 3 ]; then
s=`uniq -c $temp_file2 | awk '$1 == '$i`
echo "The user $s has logged more than 3 times"
fi
done
done

Please, check, how you thing, this script is correct ? Because, after output of my script in echo, i have that:

The user       4 21erdsf123sdfsdf   
      4 abcasbbabadab  has logged more than 3 times
The user       4 21erdsf123sdfsdf   
      4 abcasbbabadab  has logged more than 3 times
The user       4 21erdsf123sdfsdf   
      4 abcasbbabadab  has logged more than 3 times
The user       4 21erdsf123sdfsdf   
      4 abcasbbabadab  has logged more than 3 times

But i want to have output like, this:

The user       4 21erdsf123sdfsdf has logged more than 3 times
The user       4 abcasbbabadab  has logged more than 3 times

And that's all. Where i have a mistake ? Please help.